Coulombs Law Calculator

Introduction

Coulomb’s law states that the magnitude of electric force between two point charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. Using our Coulombs law calculator, you can calculate either the force of attraction or repulsion between those charges.

The force acting on the two-point charges will act along the straight line, joining the two charges. If the charges have the same sign, then the electrostatic force between them is repulsive, and if they have different signs, the force between them is attractive.

How to use the Coulombs Law Calculator?

Using the Coulombs law calculator, you can calculate the force of attraction or repulsion between two stationary and electrically charged particles.

The variables in the calculator include

Charge (q1) The amount of charge on particle 1

Charge (q2) The amount of charge on particle 2

Distance (r) The distance between the two charges

Coulomb Constant (ke) The Coulomb’s constant is also called the electric force or electrostatic constant. It is given by the following equation

Ke=14πϵ0K_e = \dfrac{1}{4 \pi\epsilon_0}

Where,

ε0 → is the vacuum electric permittivity

We consider the value of coulomb’s constant as

8.9875517923 (14) x 10^9 N m^2 C^-2

Electric Force (F) The electric force between two point charges, given by the formula

F=keq1q2r2F = \dfrac{k_e \cdot| q_1 |\cdot |q_2| }{r^2}

What is Coulomb’s Law?

Coulomb’s law states that the magnitude of electric force between two point charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. Also, the force will act along the straight line joining the two charges.

If the charges have the same sign, then the electrostatic force between them is repulsive, and if they have different signs, the force between them is attractive.

A French physicist, Charles Augustin de Coulomb, studied the interaction forces of charged particles around 1784 and came up with a theory for the electrostatic force between charged objects.

Coulomb used a torsion balance to study the strength of the forces between charged particles. It is an insulating rod with a metal-coated ball attached to one end suspended by a very thin silk thread. The ball was electrostatically charged, and when a second ball which is also electrostatically charged with the same polarity, was brought near it due to the repulsive force of the fiber, it made a certain angle with the rod. So, Coulomb could measure the force required to push the ball to make the angle.

In 1785, he published three reports on electricity and magnetism, stating the law. Subsequently, Coulomb’s law was essential to the development of the theory of electromagnetism.

How is the Electric Force Between two charged particles calculated?

The magnitude of the electrostatic force between two stationary point charges is given by the following equation

F=keq1q2r2F = \dfrac{k_e \cdot| q_1 |\cdot |q_2| }{r^2}

Where,

q1 → The charge on particle 1

q2 → The charge on particle 2

r → the distance between the two particles

ke → the proportionality constant, the value is 8.987551787 * 10^9 N m^2/C^2

ke is given by the following formula

Ke=14πϵ0K_e = \dfrac{1}{4 \pi\epsilon_0}

Where,

ε0 → is the vacuum electric permittivity, it value is 8.854 x 10^(-12) C^2/N m^2

Together, we can write the entire equation as shown below

F=14πϵ0q1q2r2F = \dfrac{1}{4 \pi\epsilon_0} \cdot \dfrac{| q_1 |\cdot |q_2| }{r^2}

Examples

Given, two point charges, q1 = 30 nC and q2 = 60 nC, are separated by a distance of 2 cm. What is the magnitude of the electric force?

F=14πϵ0q1q2r2=14π  8.854×1012C2/Nm230×109C60×109C0.022=8.988×109Nm2/C24.5  C2/m2×1012=0.040446  N\begin{aligned} F &= \dfrac{1}{4 \pi\epsilon_0} \cdot \dfrac{| q_1 |\cdot |q_2| }{r^2} \\[10pt] &= \dfrac{1}{4 \pi \; 8.854 \times 10^{-12}C^2/N \cdot m^2} \cdot \dfrac{| 30 \times 10^{-9}C |\cdot |60 \times 10^{-9}C| }{0.02^2} \\[10pt] &= 8.988 \times 10^9 N \cdot m^2/C^2 \cdot 4.5 \; C^2/m^2 \times 10^{-12} \\[10pt] &= 0.040446 \; N \end{aligned}

FAQs

How is Coulomb’s Law used in physics?

Coulomb’s Law is used in electricity, magnetism, and other fields such as chemical bonding and nuclear physics.

How does Coulomb’s Law relate to electric fields?

Coulomb’s Law is closely related to the concept of electric fields. In essence, an electric field is defined as the force experienced per unit charge. Also, the force exerted in an electric field is directly proportional to the magnitude of the test charge and the strength of the electric field.

How does Coulomb’s Law relate to charges?

Coulomb’s Law describes the interaction between charges, and it also states that charges of the same sign will repel each other, and charges of opposite signs will attract each other.

Does Coulomb’s Law apply to all types of charges?

Coulomb’s Law applies to all types of charges, whether positive or negative, as long as they are point charges. However, it does not apply to charges distributed over a surface and moving with respect to each other.

Author

hexacalculator design team

Our team blends expertise in mathematics, finance, engineering, physics, and statistics to create advanced, user-friendly calculators. We ensure accuracy, robustness, and simplicity, catering to professionals, students, and enthusiasts. Our diverse skills make complex calculations accessible and reliable for all users.